Two boxes (m1 = 43.0 kg and m2 = 39.5 kg) are connected by a light string that passes over a light, frictionless pulley. One box rests on a frictionless ramp that rises at 30.0^\circ above the horizontal (see the figure below), and the system is released from rest.
Find the acceleration of each box

Two boxes m1 430 kg and m2 395 kg are connected by a light string that passes over a light frictionless pulley One box rests on a frictionless ramp that rises a class=

Respuesta :

The net force on the system:
F = m₂g - m₁gsin(∅)
F = 39.5 x 9.81 - 43 x 9.81 x sin(30)
F = 176.58 N

Now, we use F = ma to find the acceleration on each mass.
F = m₁a₁
a₁ = 176.58 / 43
a₁ = 4.11 m/s²

F = m₂a₂
a₂ = 176.58 / 39.5
a₂ = 4.47 m/s²