Respuesta :
I think the correct answer from the choices listed above is the last option A process requires negative enthalpy and positive entropy changes to be spontaneous at all temperatures. These processes proceed when left to themselves, and in the absence of any attempt to drive them in reverse. Hope this answers the question.
Answer: negative enthalpy and positive entropy changes
Explanation:
[tex]\Delta G=\Delta H-T\Delta S[/tex]
[tex]\Delta G[/tex] = free energy change
[tex]\Delta H[/tex] = enthalpy change
T= temperature in Kelvin
[tex]\Delta S[/tex] = entropy change
[tex]\Delta G= -ve[/tex], reaction is spontaneous
If [tex]\Delta H=-ve[/tex] [tex]\Delta S=+ve[/tex]
[tex]\Delta G=(-ve)-T(+ve)[/tex]
[tex]\Delta G=(-ve)(-ve)[/tex]
[tex]\Delta G=(-ve)[/tex]
Thus reaction is spontaneous.