P(At least one sum of 8) = 1 - P(No sums of 8)
P(At least one sum of 8) = 1 - (1 - 5/36)^2
P(At least one sum of 8) = 1 - (31/36)^2
P(At least one sum of 8) = 1 - 961/1296
P(At least one sum of 8) = 335/1296
So the answer is choice B
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