Answer:
The answer is "[tex]\frac{3}{7}[/tex]"
Step-by-step explanation:
Please find the complete question:
The dilation scale factor will be the same:
[tex]=\frac{\text{Picture to Center Gap}}{\text{Related pre-image distance to the middle}}[/tex]
Throughout the picture, the distance is [tex]CP'=6[/tex], while the equivalent distance is [tex]CP=14[/tex]. The factor of scale is then[tex]=\frac{CP'}{CP} =\frac{6}{14} =\frac{3}{7}[/tex]
The decrease because if a factor of scale is below 1 and a factor of scale is higher than 1. Dilation is a reduction since [tex]\frac{3}{7}<1[/tex], therefore the scale factor is [tex]\frac{3}{7}[/tex].
The scale factor of the given dilation is; 6/14 and the dilation is a reduction
The image of the object undergoing transformation is missing and so i have attached it.
From the attached object, we se that CP = 14.
Also CP' = 6
Thus; Scale factor is 6/14
Now, reduction is reducing the dimensions while enlargement is increasing the dimensions by a scale factor.
Since the denominator of the scale factor is greater than the numerator, then there is a reduction.
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