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A man is heterozygous with a cleft chin (a dominant trait that obeys Mendel's first law) marries a normal-chinned woman and they have 10 children, all with cleft chins. What is the probability that the 11th child will have a normal chin

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maryemelsayed

Answer:

50%

Explanation:

If the male has a cleft chin, that means that his chromosomes is Aa. His wife must be aa.

             Female      Female

Male      Aa             Aa

Male      aa             aa

With Aa, the child will have a cleft chin. With aa, the child will not. So the probability is 50%.

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