Answer:
m = 51.93 grams
Explanation:
Given that,
Energy added, Q = 747 joules
The specific heat capacity of Aluminium, c = 0.899 J/g°C
The temperature goes from 105.0°C to 121.0°C.
Let the mass of the aluminum sample is m. We know that, the heat added to the system is given by :
[tex]Q=mc\Delta T\\\\m=\dfrac{Q}{c\Delta T}\\\\m=\dfrac{747}{0.899 \times (121-105)}\\\\m=51.93\ g[/tex]
So, the mass of the sample is 51.93 grams.