Is it possible to create a line segment with "infinite

steepness?

If so, do it, and explain why you think you're right

If not, explain why it's impossible.

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Answer:

No, it is not possible

Step-by-step explanation:

Required

Is it possible to have a line segment with: [tex]m = \infty[/tex]

To answer this question, we will interpret the steepness as slope.

So, we have:

[tex]m = \infty[/tex]

The interpretation of a line with: [tex]m = \infty[/tex] is:

It starts from (x,y_1) and ends at (x,y_2)

When the slope (m) is then calculated, we have:

[tex]m = \frac{y_2 - y_1}{x_1 - x_1}[/tex]

[tex]m = \frac{y_2 - y_1}{0}[/tex]

[tex]m = \infty[/tex]

What this means is that, the line has no end points.

A line segment as described here means a line that has endpoints (i.e. a finite starting point and a finite finish point)

So, we've established that: [tex]m = \infty[/tex] means no endpoints and a line segment has end points, then we can conclude that it is not possible to create a line segment with [tex]m = \infty[/tex]

Steepness of a  line is the rise or fall of it at a sharp angle.The Is it not possible to create a line segment with infinite steepness, as the slope of the such line will be infinite whether a line is plotted with finite points.

Steepness-

Steepness of a  line is the rise or fall of it at a sharp angle. The slope of the line describe the steepness of a line.

Infinite steepness-

A infinite steepness refers to a vertical line on the graph. When the line with infinite steepness plotted on the graph it is only parallel to the y axis. The change on the x axis is zero and does not move in the x axis, when a line has infinite steepness.

To understand it better suppose a line is passed through the point [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] points. For such line the slope of the line can be given as,

[tex]m=\dfrac{y_2-y_1}{x_2-x_1} [/tex]

The line with infinite steepness does not move in the x axis. The coordinate of the x axis same for the line. Thus,

[tex]x_2=x_1[/tex]

The slope for such line is,

[tex]m=\dfrac{y_2-y_1}{x_1-x_1} [/tex]

[tex]m=\dfrac{y_2-y_1}{0} [/tex]

[tex]m=\infty[/tex]

Thus the slope of the line is infinite. But the line With no finite point is not possible to plot.

Hence the Is it not possible to create a line segment with "infinite steepness, as the slope of the such line will be infinite whether a line is plotted with finite points.

Learn more about the steepness of the line here;

https://brainly.com/question/806542