Answer:
The correct answer is "6.015×10⁴ J/K".
Explanation:
The given values are:
Mass of water,
= 10 kg
Latent heat of boiling,
= 2257 kJ
Constant temperature,
= 100°C
The entropy change will be:
= [tex]\frac{mass\times latent \ heat \ of \ boiling}{temperature}[/tex]
On substituting the values, we get
= [tex]\frac{10\times 2257\times 1000}{(273+100)K}[/tex]
= [tex]\frac{22,570,000}{373K}[/tex]
= [tex]6.051\times 10^4 \ J/K[/tex]
