Respuesta :
Answer:
Given:
height of tree[h]=275ft
diameter [d]=25ft
we have
[i] Volume of cylindrical tree =πr²h π×(12.5)²×275=134990.3ft³(approx)
[ii] Lateral surface area =2πrh= 2×π×12.5×275=21598.5ft²
[iii] Weight of General Sherman = 134990.3ft³×30
=4,049,709pounds
[iv] Weight of blue whale = 400,000 pounds.
No. of whale weighted equal to the tree 4,049,709/400,000 =10.12
so 10 whale rounded.
Step-by-step explanation:
To Find :-
- What is the volume of the tree?
- What is the surface area of the tree?
Solution :-
Since here we are assuming this tree to be cylinder therefore,
> Volume = πr²h
> Volume = 3.14 × (12.5)² × 275
> Volume = 134990.34 ft²
And we know that lateral surface area is ,
> LSA = 2πrh
> LSA = 2 × 3.14 × 12.5 × 275
> LSA = 21598.5 ft
Part C :-
> Weight = Volume × 30
> Weight = 134990.34 × 30
> Weight = 4049709 pounds .
And ,
> no. of whale = 4049709/400000
> no. of whale = 10.12
> No. of whale = 10 ( rounding off)