The value of x for which the trinomial 2x^2−x+55 equal to the square of binomial x+5 is 5 and 6
Given the equation 2x^2−x+55, if the expression is equal to the square of binomial x + 5, then;
2x^2−x+55 = (x+5)^2
2x^2−x+55 = x^2 + 10x + 25
Collect the like terms;
2x^2-x^2-x-10x+55-25 = 0
x^2 - 11x + 30 = 0
Factorize the result
x^2 - 6x - 5x + 30 =0
x(x-6)-5(x-6) = 0
x-5 = 0 and x - 6 = 0
x = 5 and 6
Hence the value of x for which the trinomial 2x^2−x+55 equal to the square of binomial x+5 is 5 and 6
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