Answer:
[tex]Perimeter =58[/tex]
Step-by-step explanation:
Given
[tex]AB = 24[/tex]
See attachment
Required
The perimeter of ABC
First, calculate the lengths of AC and BC.
From the attachment.
[tex]Ax = Az =10[/tex]
[tex]Cx = Cy = 5[/tex]
[tex]By =Bz[/tex]
So, we have:
[tex]AC = 10 + Cx[/tex]
[tex]AC = 10 + 5[/tex]
[tex]AC = 15[/tex]
Also:
[tex]Az + Bz = AB[/tex]
[tex]Az + Bz = 24[/tex]
Recall that: [tex]Ax = Az =10[/tex]
So:
[tex]10 + Bz = 24[/tex]
[tex]Bz = 24 - 10[/tex]
[tex]Bz = 14[/tex]
So, we have:
[tex]By = Bz = 14[/tex]
To calculate BC, we have:
[tex]BC = 5 + By[/tex]
[tex]BC=5+14[/tex]
[tex]BC = 19[/tex]
The perimeter is then calculated as:
[tex]Perimeter = AB + BC + AC[/tex]
[tex]Perimeter = 24 + 19 + 15[/tex]
[tex]Perimeter = 58[/tex]
