Answer:
[tex]P_2=2.6kPa[/tex]
Explanation:
Hello there!
In this case, according to the Gay-Lussac's gas law, which illustrates the pressure-temperature behavior as a directly proportional relationship:
[tex]\frac{P_2}{T_2}=\frac{P_1}{T_1}[/tex]
We can solve for the final pressure as shown below:
[tex]P_2=\frac{P_1T_2}{T_1}[/tex]
Thus, we plug in the initial pressure and temperature and final temperature to obtain:
[tex]P_2=\frac{6.58kPa*210K}{540K}\\\\ P_2=2.6kPa[/tex]
Which is not among the choices.
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