Independent Practice

A Bicyclist's Practices

Elaspsed Time----------Distance

10 min----------3 mi

25 min----------7.5 mi

A bicyclist traveled at a constant speed during a timed practice period. Write an equation and find the distance the cyclist traveled in 30 min.

A.
d = 0.3t; 9 mi

B.
d = 30t; 900 mi

C.
d= 10/3t; 100 mi

D.
d = 3t; 90 mi

Bicycling A bicyclist traveled at a constant speed during a timed practice period. Write a proportion to find the distance the cyclist traveled in 30 min.

elapsed time distance

10 min 3 mi

25 min 7.5 mi

Graph it. :)

Start at (0,0), then at 10 min. on the x-axis, go 3 spaces up on the y-axis and plot a point. Do the same for 25 min. and 7.5 miles. Draw a line through all of those points, and see where the line hits on the y-axis when the x-axis is at 30 min. :)

If two things vary directly it means their ratio is a constant. Therefore from the formula rt=d. r=d/t, r=3/10 or 7.5/25 which reduces to 3/10. This is the constant speed,the lable is mi/min. Now use (d/30)=(3/10) and solve for d. Cross multiply and 10d=90, or d=9 mi

fichoh fichoh · Answer 2 · 2021-09-03T21:09:11+02:00

Using the information given, the distance formular = 0.3t ; distance covered in 30 minutes = 9 miles

Since the speed is constant :

We could use either of distance and elapsed time values to create an equation :

Elaspsed time - - - - Distance

10 minutes _____ 3 miles

Recall :

Distance covered = speed × time

Distance covered = speed × time Speed = distance / time

Speed of bicyclist is thus :

(3 miles / 10 minutes) = speed

Speed = 0.3 miles per minute

Hence,

Distance = 0.3 × time

For a travel time of 30 minutes ;

Distance covered = 0.3 × 30 = 9 miles

Hence, distance formular = 0.3t ; distance covered in 30 minutes = 9 miles

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