Answer:
[tex]V_{base}=6.0mL[/tex]
Explanation:
Hello there!
In this case, by considering that the reaction between sodium hydroxide and hydrochloric acid is in a 1:1 mole ratio of these two reactants, we are able to use the following equation relating the concentration and volume of each one:
[tex]M_{acid}V_{acid}=M_{base}V_{base}[/tex]
In such a way, by solving for the volume of the base, we will obtain:
[tex]V_{base}=\frac{M_{acid}V_{acid}}{M_{base}} \\\\V_{base}=\frac{0.5M*24mL}{2.0M}\\\\V_{base}=6.0mL[/tex]
Regards!
