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1) Let X represent the number of tires with low air pressure on a randomly chosen car. The probability of distribution of X is as follows:

X 0 1 2 3 4

P(X) 0.1 0.2 0.4 0.2 0,1


a) Find the probability of 1 tire with low air pressure P (1) =


b) Find the probability of more than 2 tires having low air pressure P (more than 2) =


c) P (all 4 tires) =


d) Compute the expected number of tires with low air pressure.


e) Compute the standard deviation for the number of tires with low air pressure.

Respuesta :

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Answer:

0.2 ; 0.3 ; 0.1 ; 2

Step-by-step explanation:

X 0 1 2 3 4

P(X) 0.1 0.2 0.4 0.2 0,1

a) Find the probability of 1 tire with low air pressure P (1) :

From probability distribution table Given :

P(1) = 0.2

b) Find the probability of more than 2 tires having low air pressure P (more than 2) =

P(x > 2) = p(3) + p(4)

P(x > 2) = 0.2 + 0.1 = 0.3

c) P (all 4 tires)

From the table :

P(x = 4) = 0.1

d) Compute the expected number of tires with low air pressure.

E(X) = Σx * p(x)

E(x) = (0*0.1) + (1*0.2) + (2*0.4) + (3*0.2) + (4*0.1) = 2

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