gzz24
contestada

A rectangular carport has area of one 50 ft.The width of the carport is 5 feet less than twice its length. Find the length and width of the carport

Width= ? feet,
Length= ? feet

Respuesta :

Answer:

[tex]Length = 10ft[/tex]

[tex]Width = 15ft[/tex]

Step-by-step explanation:

Given

[tex]W= Width\\ L = Length[/tex]

[tex]Area = 150[/tex]

[tex]W=2*L- 5[/tex]

Required

Determine the dimension

Area is calculated as:

[tex]Area = L * W[/tex]

So, we have:

[tex]L * W = 150[/tex]

Substitute: [tex]W=2*L- 5[/tex]

[tex]L * (2*L-5) = 150[/tex]

[tex]L * (2L-5) = 150[/tex]

Open bracket

[tex]2L^2 - 5L = 150[/tex]

Rewrite as:

[tex]2L^2 - 5L - 150=0[/tex]

Expand

[tex]2L^2 -20L + 15L - 150 = 0[/tex]

Factorize:

[tex]2L(L -10) + 15(L - 10) = 0[/tex]

[tex](2L + 15) (L - 10) = 0[/tex]

Split

[tex]2L + 15=0[/tex] or [tex]L -10 = 0[/tex]

Solve for L

[tex]2L =-15[/tex] or [tex]L = 10[/tex]

L cannot be negative

So:

[tex]L = 10[/tex]

Substitute [tex]L = 10[/tex] in [tex]W=2*L- 5[/tex]

[tex]W = 2 * 10 - 5[/tex]

[tex]W = 20 - 5[/tex]

[tex]W = 15[/tex]

Hence:

[tex]Length = 10ft[/tex]

[tex]Width = 15ft[/tex]