Answer:
f = 409.6 Hz, the woman hears a higher frequency sound
Explanation:
This is a Doppler effect problem, which is described by the equation for the case of a fixed observer
f = fo [tex]\frac{v}{v \pm v_s}[/tex]
where the negative sign is for the source approaching the observer
in this case the car is the one that emits the sound and moves away from the intersection
let's calculate
f = 400 [tex]\frac{343}{343-8}[/tex]
f = 409.6 Hz
therefore the woman hears a higher frequency sound
