Respuesta :
For x = -5 the equation [tex]-8(x+5) = -3x\;-7\;+x\;-3[/tex] is a true equation. Hence, OPTION (B) IS CORRECT.
We have the following equation -
[tex]-8(x+5) = -3x\;-7\;+x\;-3[/tex]
We have to find the value of x that makes this equation true.
How can you say that the equation [tex]x^{2} = 2x[/tex] is a true equation at x = 0 and x = 2 ?
In order to prove that the equation is true at x = 2 and x = 0, we have to prove that the left hand side of the equation equals the right hand side of the equation, if we substitute 2 or 0 in place of x Solving the equation to find the value of x -
[tex]x^{2} =2x\\x^{2} -2x=0\\[/tex]
x (x - 2) = 0
x = 0 or x - 2 = 0
Test case 1 : for [tex]x = 2[/tex]
[tex]x^{2} =2x\\2^{2} =2 (2)\\4 =4[/tex]
LHS = RHS
Test case 2 : for [tex]x =0[/tex]
[tex]x^{2} =2x[/tex]
[tex]0^{2} = 2(0)[/tex]
[tex]0 = 0[/tex]
LHS = RHS
Hence, the equation [tex]x^{2} = 2x[/tex] is a true equation for [tex]x=0[/tex] and [tex]x=2[/tex]
We can use the similar approach in the equation -
[tex]-8(x+5) = -3x\;-7\;+x\;-3[/tex]
to find the value of [tex]x[/tex] for which the equation is true.
-8(x+5) = -3x-7+x-3
-8x-40=-2x-10
-8x+2x = -10+40
-6x = 30
x=-5
Hence, for x = -5 the equation [tex]-8(x+5) = -3x\;-7\;+x\;-3[/tex] is true equation.
To solve more questions on True equations, visit the link below -
https://brainly.com/question/9447244
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