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Two carts, cart AA (mass 4.00 kgkg) and cart BB (mass 6.50 kgkg) move on a frictionless, horizontal track. Initially, cart BB is at rest and cart AA is moving toward it at 4.00 m/sm/s. The carts are equipped with ideal spring bumpers, meaning they conserve energy. The collision is head-on, so all motion before and after the collision is along a straight line. Let x x be the direction of the initial motion of cart AA.

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okpalawalter8

Answer:

[tex]V{_a}'=-0.95m/s[/tex]

Explanation:

From the question we are told that:

Mass of cart A [tex]m_a=4kg[/tex]

Mass of cart B [tex]m_a=6.50kg[/tex]

Speed of cart AA [tex]V-{a}=4.00[/tex]

Generally the equation for velocity of  A after collision [tex]V{_a}'[/tex] is mathematically given by

[tex]V_{a}'=\frac{M_a-M_b}{M_a+M+b} V_a[/tex]

[tex]V{_a}'=\frac{4-6.5}{4+M6.5} *4[/tex]

[tex]V{_a}'=\frac{4-6.5}{4+M6.5} *4[/tex]

[tex]V{_a}'=-0.95m/s[/tex]