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The formulas for the binary ionic compounds are:
- a. potassium and iodine: KI.
- b. magnesium and chlorine: MgCl₂.
- c. sodium and sulfur: Na₂S.
- d. aluminum and sulfur: Al₂S₃.
- e. aluminum and nitrogen: AlN.
We want to write the formulas of different binary ionic compounds. to do so, we need to consider the octet's rule.
What is the octet's rule?
The octet's rule establishes that atoms will lose, gain or share electrons to achieve the electron configuration of the nearest noble gas (8 valence electrons except for He with 2).
a. potassium and iodine
K has 1 valence electron so it will lose 1 electron to form K⁺. I has 7 valence electrons so it will gain 1 electron to form I⁻. The neutral compound between K⁺ and I⁻ is KI.
b. magnesium and chlorine
Mg has 2 valence electrons so it will lose 2 electrons to form Mg⁺². Cl has 7 valence electrons so it will gain 1 electron to form Cl⁻. The neutral compound between Mg⁺²⁺ and Cl⁻ is MgCl₂.
c. sodium and sulfur
Na has 1 valence electron so it will lose 1 electron to form Na⁺. S has 6 valence electrons so it will gain 2 electrons to form S⁻². The neutral compound between Na⁺ and S⁻² is Na₂S.
d. aluminum and sulfur
Al has 3 valence electrons so it will lose 3 electrons to form Al³⁺. S has 6 valence electrons so it will gain 2 electrons to form S⁻². The neutral compound between Al³⁺ and S⁻² is Al₂S₃.
e. aluminum and nitrogen
Al has 3 valence electrons so it will lose 3 electrons to form Al³⁺. N has 5 valence electrons so it will gain 3 electrons to form N³⁻. The neutral compound between Al³⁺ and N³⁻ is AlN.
The formulas for the binary ionic compounds are:
- a. potassium and iodine: KI.
- b. magnesium and chlorine: MgCl₂.
- c. sodium and sulfur: Na₂S.
- d. aluminum and sulfur: Al₂S₃.
- e. aluminum and nitrogen: AlN.
Learn more about binary compounds here: https://brainly.com/question/7960132
