Answer:
[tex]H^++NH_3\rightleftharpoons NH_4^+[/tex]
Explanation:
Hello there!
In this case, since the buffer is not given, we assume it is based off ammonia, it means the ammonia-ammonium buffer, whereas the ammonia is the weak base and the ammonium ion stands for the conjugate acid. In such a way, when adding HI to the solution, the base of the buffer, NH3, reacts with the former to promote the following chemical reaction:
[tex]H^++NH_3\rightleftharpoons NH_4^+[/tex]
Because the HI is totally ionized in solution so the iodide ion becomes an spectator one.
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Answer:
the above answer is wrong
Explanation:
its really not but the mastering chemistry says it is
