Respuesta :
Answer:
The temperature is 12.35 C.
Explanation:
An ideal gas is a theoretical gas that is considered to be composed of point particles that move randomly and do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.
An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:
P * V = n * R * T
In this case:
- P= 2.15 atm
- V= 35.28 L
- n= 3.24 moles
- R= 0.082 [tex]\frac{atm*L}{mol*K}[/tex]
- T= ?
Replacing:
2.15 atm* 35.28 L= 3.24 moles* 0.082[tex]\frac{atm*L}{mol*K}[/tex] * T
Solving:
[tex]T=\frac{2.15 atm* 35.28 L}{3.24 moles* 0.082\frac{atm*L}{mol*K}}[/tex]
T=285.5 K= 12.35 C (being 273.15 K= 0 C)
The temperature is 12.35 C.
The relation between the moles, volume, temperature, and pressure is given by the ideal gas equation. The temperature of a gas is 12.35 celsius.
What is the ideal gas law?
The ideal gas law is the hypothetical gas law that depicts the relation between pressure, volume, moles of the compound, and the temperature of the gas.
The ideal gas equation is given as,
[tex]\rm PV = nRT[/tex]
Given,
Pressure (P) = 2.15 atm
Volume (V) = 35.28 L
Number of moles (n) = 3.24 mol
Gas constant (R) = 0.082
Temperature (T) = ?
Substituting values in the above equation, the temperature is calculated as:
[tex]\begin{aligned} \rm T &= \rm \dfrac{PV}{nR}\\\\&= \dfrac{2.15\times 35.28}{3.24 \times 0.082}\\\\&= 286.23 \;\rm K\end{aligned}[/tex]
Therefore, 12.35 degrees Celsius is the temperature of the gas.
Learn more about ideal gas law here:
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