Answer:
Hello your question is incomplete attached below is the complete question
answer : 1596 ± 2.861 [tex]\sqrt{\frac{1580^2 }{20 } +\frac{2350^2 }{20 } }[/tex] ------ ( A )
Step-by-step explanation:
I will use excel function to resolve this question
Determine the 99% confidence of interval for the difference in mean number of steps by all people
∝ = 0.01
critical value ( t ) = 2.861 ( = TINV ( 0.01, 19 )
Given that :
S1 = 1580
S2 = 2350
n1 = 20
n2 = 20
Difference in mean = x1 - x2 = 1596
Margin of Error = t * [tex]\sqrt{\frac{S^2_{1} }{n_{1} } +\frac{s^2_{2} }{n_{2} } }[/tex]
∴ 99% confidence of interval
= 1596 ± 2.861 [tex]\sqrt{\frac{1580^2 }{20 } +\frac{2350^2 }{20 } }[/tex] ------
