Create an equation for a different linear function that has twice the rate of change and the same initial value as the one represented by the table
Can someone help me please
No links :/ .
Answer: y=x+3.5 The function of the original equation (the data table) is y=1/2x+3.5 So 1/2 times 2 is 1 and the y intercept (the initial value) is the same! I hope I helped
