Step-by-step explanation:
LET THE Point 1 A and point 2 is B
(AB) ^2=(-9-(-3))^2+ (5-(-6))^2+(-4-7)^2=278
AB=16.67 length unit
Midpoint
X=-9-3/2 =-6
Y=5-6/2=-0.5
Z=-4+7/2=-1.5
The distance between points (−3,−6,7) and (−9,5,−4) is 16.6 units, and midpoints are (-6, -0.5, -1.5).
Distance between two points (x₁, y₁, z₁) and (x₂, y₂, z₂) is determined by the following as D² = (x₂-x₁)² + (y₂-y₁)² + (z₂-z₁)²
The midpoint of the line joining (x₁, y₁, z₁) and (x₂, y₂, z₂) is given by :
{(x₂+x₁)/2 , (y₂+y₁)/2 , (z₂+z₁)/2}
To determine the distance between points (−3,−6,7) and (−9,5,−4)
Let mid points X, Y, and Z
The given points : (−3,−6,7) and (−9,5,−4)
Distance between points (−3,−6,7) and (−9,5,−4) :
D² = (x₂-x₁)² + (y₂-y₁)² + (z₂-z₁)²
D² =(-9-(-3))²+ (5-(-6))²+(-4-7)² = 278
D = √278
D = 16.6 units
The midpoint of the line joining (−3,−6,7) and (−9,5,−4) :
X = (-9-3)/2 = -6
Y =(5-6)/2 = -0.5
Z =(-4+7)/2 = -1.5
Hence, the distance between points (−3,−6,7) and (−9,5,−4) is 16.6 units, and midpoints are (-6, -0.5, -1.5).
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