Answer:
435.38 L
Explanation:
From the question,
Applying ideal gas equation,
PV = nRT................... Equation 1
Where P = Pressure, V = Volume, n = number of moles, R = molar gas constant, T = Temperature.
Since Temperature and Pressure were constant,
V ∝ n
V/n = V'/n'.................... Equation 2
Where V and V' = the initial and final Volume of Ar respectively, n and n' = the initial and final moles of Ar respectively
make V' the subject of the equation
V' = Vn'/n............... Equation 3
Given: V = 100 L, n = 3.25 mol, n' = 14.15
Substitute into equation 3
V' = (100×14.14)/3.25
V' = 435.38 L
4.15 mole of Ar gas occupy the volume of 435.38 L under same condition.
Ideal gas equation for any gas at standard condition is define as:
PV = nRT, where
P = Pressure,
V = Volume,
n = number of moles,
R = molar gas constant,
T = Temperature.
In the question it is given that pressure and temperature for the expansion is constant, so ideal gas equation becomes:
V/n = V'/n', where
V = initial volume of Ar = 100 L (given)
V' = final Volume of Ar = to find?
n = initial moles of Ar = 3.25 mole (given)
n' = final moles of Ar = 14.15 mole (given)
Now we calculate the final volume as:
V' = (100×14.14)/3.25 = 435.38 L
Hence, 435.38 L is the occupied volume.
To know more about ideal gas equation, visit the below link:
https://brainly.com/question/20348074
