Answer:
x = 30
Step-by-step explanation:
[tex] \triangle JLK\sim\triangle PQR[/tex] (given)
[tex] \therefore \frac{JL}{PQ}=\frac{LK}{QR} [/tex]
(corresponding sides of similar triangles)
[tex] \therefore \frac{20}{x}=\frac{22}{33} [/tex]
[tex] \therefore \frac{20}{x}=\frac{2}{3} [/tex]
[tex] \therefore x=\frac{20\times 3}{2} [/tex]
[tex] \therefore x=\frac{60}{2} [/tex]
[tex] \therefore x=30 [/tex]
Or using scale factor:
Scale factor = 33/22 = 3/2
x = 20*3/2
x = 10*3
x = 30
