graveyardgecko
contestada

Enlarge shape A by scale factor 4 with centre of enlargement (-2, 2).
8
7
6
5
4
(-3, 3)
(-1,3)
A.
N
(-3, 1)
(-1,1
+
-8
-1
-6
at
-3
-2
-1
+
4
2
3
5
6
8
-1
-2
-3
-4
-5 +
-6
-7 +
-8
What are the coordinates of the vertices of the image?​

Enlarge shape A by scale factor 4 with centre of enlargement 2 2876543 313AN3 111816at32142356812345 67 8What are the coordinates of the vertices of the image class=

Respuesta :

ivycoveredwalls

Answer:

(-6, 6), (2, 6), (-6, -2), (2, -2)

Step-by-step explanation:

Unfortunately, you can't just multiply the coordinates of the corners by 4.  That works if the center of the enlargement is the origin, (0, 0).  So you have to do this enlargement in 3 steps for each of the corner points.

Step 1  Move the point right 2 units and down 2 units [tex](x,\,y) \to (x+2,\,y-2)[/tex].

The reason for this step is that this is what you do to move the center (-2, 2) to (0, 0).

Step 2  Multiply the new coordinates by 4.

Step 3 Move the new point left 2 units and up 2 units [tex](x,\,y) \to (x-2,\,y+2)[/tex].

Example:  using the upper-left corner (-3, 3)...

Step 1  [tex](-3,\,3) \to (-1,\,1)[/tex]

Step 2  [tex](-1,\,1) \to (-4,\,4)[/tex]

Step 3  [tex](-4,\,4) \to (-6,\,6)[/tex]

Repeat the process with the other three corners.

raphealnwobi

The coordinates of the vertices of the image is A'(-6, -2), B'(-6, 6), C'(2, -2) and D'(2, 6)

What is dilation?

Dilation is the increase or decrease in the size of a figure by a scale factor of k.

The vertices is at A(-3, 1), B(-3, 3), C(-1, 1) and D(-1, 3). The figure is enlarge by a scale factor 4 with centre of enlargement (-2, 2). Hence:

A' = (4(-3-(-2)) + (-2), 4(1 - 2) + 2) = (-6, -2)

B' = (4(-3-(-2)) + (-2), 4(3 - 2) + 2) = (-6, 6)

C' = (4(-1-(-2)) + (-2), 4(1 - 2) + 2) = (2, -2)

D' = (4(-1-(-2)) + (-2), 4(3 - 2) + 2) = (2, 6)

The coordinates of the vertices of the image is A'(-6, -2), B'(-6, 6), C'(2, -2) and D'(2, 6)

Find out more on dilation at: https://brainly.com/question/10253650

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