Answer:
The coordinates of the vertices of triangle A'B'C' are [tex]A'(x,y) = (0,-4)[/tex], [tex]B'(x,y) = (2,-1)[/tex] and [tex]C'(x,y) = (3,-5)[/tex].
Step-by-step explanation:
According to this statement, triangle ABC must be translated 5 units in the -y direction to form triangle A'B'C'. We need to use the following operations:
[tex]A'(x,y) = A(x,y) +(0,-5)[/tex] (1)
[tex]B'(x,y) = B(x,y) +(0,-5)[/tex] (2)
[tex]C'(x,y) = C(x,y) + (0,-5)[/tex] (3)
If we know that [tex]A(x,y) = (0,1)[/tex], [tex]B(x,y) = (2,4)[/tex] and [tex]C(x,y) = (3,0)[/tex], then the new vertices of the rectangle are, respectively:
[tex]A'(x,y) = (0,-4)[/tex], [tex]B'(x,y) = (2,-1)[/tex], [tex]C'(x,y) = (3,-5)[/tex]
