Answer:
t(s) is in the acceptance region. We accept H₀ we don´t have enough evidence to justify differences in the procedures
Step-by-step explanation:
Traditional procedure bring as μ = 8,6 h
Sample Information:
Sample size n = 26
Sample mean x = 8,4
Sample standard deviation s = 1
With n = 26 unknown population standard deviation, and population with normal distribution we should use t-student test
then n = 26 degree of freedom df = n - 1 df = 25
significance level 0,1 with that information we look in t-student table t (c) ( two tails test)
t(c) = - 1,708
Test Hypothesis
Null hypothesis H₀ x = μ
Alternative Hypothesis Hₐ x ≠ μ
Alternative hypothesis indicates that the test should considered two tails
To calculate t(s)
t(s) = ( x - μ ) / s/√n
t(s) = ( 8,4 - 8,6 )/ 1/√26
t(s) = - 0,2 * 5,09 / 1
t(s) = - 1,019
Comparing |t(s)| and |t(c)|
1,019 < 1,708 |t(s)| < |t(c)|
t(s) is in the acceptance region. We accept H₀ we don´t have enough evidence to justify differences in the procedures