Answer:
462nm
Explanation:
E=hf
c=fλ
E=hc/λ
The relation between the wavelength λ of a photon and its energy E is following: E=hc/λ where h = 6.626×10⁻³⁴ J⋅s is Planck’s constant, c = 3×10⁸ m/s is the speed of light. If E = 4.56×10^⁻¹⁹ J then λ = 463nm(nano meter)
The wavelength of a photon with an energy of 4.56×10⁻¹⁹ J is 463nm (nanometer)
Define the wavelength of a photon.
Each photon has a wavelength and a frequency. The wavelength is defined as the distance between two peaks of the electric field with the same vector.
A photon is the smallest element of electromagnetic radiation. You can think of a photon as a packet of energy travelling at the speed of light. There is no constant wavelength of a photon, it is dependent on how much energy the photon carries.
The mathematical relationship can be written as
E=hc/ λ
In terms of wavelength,
λ=hc/E
- h is planks constant
- c is the speed of light
- E is the energy of the photon
Where h = 6.626×10⁻³⁴ J⋅s is Planck’s constant and c = 3×10⁸ m/s is the speed of light.
If E = 4.56×10⁻¹⁹ J then λ = 463nm (nano meter)
Hence, the wavelength of a photon with an energy of 4.56×10⁻¹⁹ J is 463nm(nanometer)
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