The truck is going fast by the velocity of 9.2 m/s at the bottom.
What is speed?
The speed is the ratio of distance moved by the object and time taken to cover it.
The height of the slope is
h =Lsinθ = 22sin 8.30° = 3.176m
Change in potential energy ΔU = -mgh
if final velocity of the truck is v, then kinetic energy of truck from top to bottom is
ΔK.E = 1/2 x m x (v² -v₀²) where v₀ =4.71 m/s, m =3770kg
From the law of conservation of conservation of energy, ΔK.E +ΔU =0
Substitute the expressions and their values provided in the question, we have
1/2 x m x (v² -v₀²) -mgh =0
v = 9.19 m/s
Thus, the velocity at the bottom of the slope is 9.19 m/s.
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