For the​ following, indicate whether a confidence interval for a proportion or mean should be constructed to estimate the variable of interest. A researcher with a golf association obtained a random sample of 25 rounds of golf on a Saturday morning and recorded the time it took to complete the round.

The goal of the research was to estimate the amount of time it typically takes to complete a round of golf on Saturday morning. The confidence interval for a population _____________ proportion mean should be constructed because the variable of interest is _________ score, time to complete the round, whether the round was completed in less than 5 hours or not, which is a ___________ qualitative quantitative variable.

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Answer:

The confidence interval for a population mean proportion mean should be constructed because the variable of interest is time to complete the round, which is a quantitative variable.

Step-by-step explanation:

A researcher with a golf association obtained a random sample of 25 rounds of golf on a Saturday morning and recorded the time it took to complete the round.

Time is the number of hours, so it is mean, and not proportion.

Variable of interest is time to complete the round, and since it is measured in hours it is a quantitative variable.

The answer is:

The confidence interval for a population mean proportion mean should be constructed because the variable of interest is time to complete the round, which is a quantitative variable.

The confidence interval for a population of variable of interest time is normally distributed  . The Confidence interval for proportion mean should be constructed because the  variable of interest is the time taken to complete one round of golf score, time to complete the round.

Whether the round was completed in less than 5 hours or not is depending upon the calculations involved and variables  of  the sample taken which is a  quantitative variable.

The confidence interval for the normally distributed variable of interest is determined by the equation as formulated below

[tex]\rm Confidence\; Interval = \mu - Z \sigma/\sqrt{n} \;\;to \; \mu + Z \sigma/\sqrt{n} \\Where\\\mu = Sample\; mean \\Z = Z \; score \\\\\sigma = Sample\; standard \; deviation \\n = Sample \; size[/tex]

We have to  indicate whether a confidence interval for a proportion or mean should be constructed to estimate the variable of interest.

A researcher with a golf association obtained a random sample of 25 rounds of golf on a Saturday morning and recorded the time it took to complete the round.

The goal of the research was to estimate the amount of time  it typically takes to complete a round of golf on Saturday morning

As given by the language of the question we can conclude that the variable of interest is the time taken to complete one round of golf.

So we consider that the time variable is normally distributed

Also time variable is quantitative variable.

So we can fill in the blanks

The confidence interval for a population of variable of interest time is normally distributed .The Confidence interval for  proportion mean should be constructed because the  variable of interest is the time taken to complete one round of golf score, time to complete the round.

Whether the round was completed in less than 5 hours or not is depending upon the calculations involved and variables  of  the sample taken which is a  quantitative variable.

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https://brainly.com/question/24131141