Respuesta :
Answer:
The volume of the flask is 20.245 litres .
Explanation:
We are given with following information-
[tex]PV=nRT[/tex] -------- 1
where R =[tex]0.0821L.atom/mole.K[/tex]
Molar mass of [tex]PCl_5=208.22g/mole[/tex]
The given chemical equation is -
[tex]2P _(_s_)+5Cl_2 _(_g_)\rightarrow2PCl_5 _(_s_)[/tex] --------- 2
Now , calculation -
Mass of [tex]PCl_5[/tex] formed = 118g
Molar mass of [tex]PCl_5[/tex] = [tex]208.22g/mole[/tex]
Mole = [tex]\frac{mass (g)}{molar mass}[/tex]
Therefore , moles of [tex]PCl_5[/tex] formed = [tex]\frac{118}{208.22}[/tex]
From equation 2 , we get to know that ,
2mole [tex]PCl_5[/tex] formed from 5 mole [tex]Cl_2 _(_g_)[/tex]
Therefore , [tex]\frac{118}{208.22}[/tex] mole [tex]PCl_5[/tex] formed from [tex]\frac{5}{2} \times\frac{118}{208.22}[/tex] mole [tex]Cl_2 _(_g_)[/tex]
Moles of [tex]Cl_2 _(_g_)[/tex] used =[tex]\frac{5\times118}{2\times208.22} mole[/tex]
R= [tex]0.0821L.atom/mole.K[/tex]
Pressure (P)= 1.85atm
Temperature (T)= 322K
Moles of [tex]Cl_2 _(_g_)[/tex] (n)= [tex]\frac{5}{2} \times\frac{118}{208.22}[/tex] moles
Applying the formula above in 1 equation , that is
PV = nRT
putting the given values -
[tex]1.85 \times V=\frac{5}{2} \times\frac{118}{208.22}\times0.0821\times322[/tex]
V = 20.245 litres.
Hence , the volume of the flask is 20.245 litres .
