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An arm wrestler is the champion for a period of 75 hours. (Here, by an hour, we mean a period starting from an exact hour, such as 1 P.M., until the next hour.) The arm wrestler had at least one match an hour, but no more than 125 total matches. Show that there is a period of consecutive hours during which the arm wrestler had exactly 24 matches.

Respuesta :

Answer:

The answer is "In the i-th to J-th hour, the Wrestler played only 24 match-ups".

Step-by-step explanation:

Let [tex]x_i[/tex] label the number of teams played by the wrestler for [tex]1 \leq i \leq 75[/tex], after i-th hour, where [tex]1 \leq x_i \leq 125[/tex].   This also means [tex]25 \leq x_i + 24 \leq 149[/tex]. The Pigeonhole Principle means that [tex]\ni i \neq j \ni x i+ 24 = x ,j[/tex] is played exactly 24 matches  between the i-th and j-th-hours end. Thus, 150 integrals [tex]x_1,x_2,......x_{75}, x_1+24,x_2+24.[/tex]  In the i-th to J-th hour, the Wrestler played only 24 match-ups.

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