Answer:
[tex]V_2=435.4L[/tex]
Explanation:
Hello there!
In this case, for this gas problem, we can use the Avogadro's law as a way to understand the volume-mole behavior as a directly proportional relationship:
[tex]\frac{V_2}{n_2}=\frac{V_1}{n_1}[/tex]
Thus, given the initial and final moles and the initial volume, we obtain the following final volume:
[tex]V_2=\frac{V_1n_2}{n_1} =\frac{100.L*14.15mol}{3.25mol}\\\\V_2=435.4L[/tex]
Best regards.
