Respuesta :
Answer:
A. After 2.5 sec and .25 sec the ball was at a height of 15 ft.
B. 2.86 sec is the time it takes to hit the ground
Step-by-step explanation:
A. let h = 15
then 15 = -16t^2 + 44t + 5
16t^2 - 44t + 10 =0
2(8t^2 - 22t + 5) = 0
2(2t - 5)(4t - 1) = 0
t = 5/2 = 2.5 or t = 1/4 = .25
After 2.5 sec and .25 sec the ball was at a height of 15 ft.
B. Let h = 0.
-16t^2 + 44t + 5 = 0
Use the quadratic formula to find t. (I will let you do that)
t = 2.85929... or t = -.10929...
t cannot be negative, so 2.86 sec is the time it takes to hit the ground
The answer of A is After 2.5 sec and 0.25 sec the ball was at a height of 15 ft and the answer of B is 2.86 sec is the time it takes to hit the ground.
A. let h = 15
What is the quadratic equation?
[tex]ax^2+bx+c=0[/tex]
a, b, c = known numbers, where a ≠ 0
x = the unknown
then 15 = -16t^2 + 44t + 5
16t^2 - 44t + 10 =0
2(8t^2 - 22t + 5) = 0
2(2t - 5)(4t - 1) = 0
t = 5/2 = 2.5 or t = 1/4 = 0.25
After 2.5 sec and 0.25 sec the ball was at a height of 15 ft.
B. Let h = 0.
-16t^2 + 44t + 5 = 0
Use the quadratic formula to find t.
t = 2.85929... or t = -.10929...
t cannot be negative, So 2.86 sec is the time it takes to hit the ground.
To learn more about the quadratic equation visit:
https://brainly.com/question/1214333
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