Answer:
n = 0.045 mol.
Explanation:
Hello there!
In this case, according to the given problem, we can firstly set up the ideal gas equation as shown below:
[tex]PV=nRT[/tex]
Thus, as we are asked to calculate the moles, we proceed as follows:
[tex]n=\frac{PV}{RT}[/tex]
Therefore, we plug in the given data to obtain:
[tex]n=\frac{760mmHg*\frac{1atm}{760mmHg}*1.0L}{0.08206\frac{atm*L}{mol*K}*273K} \\\\n=0.045mol[/tex]
Best regards!
