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The pressure of a sample of argon gas was increased from 3.14 atm to 7.98 at a constant temperature. If the final volume of argon sample was 14.2 L what what’s the initial volume of the argon sample? Assume ideal behavior

Respuesta :

Stephen46

Answer:

36.09 L

Explanation:

The initial volume can be found by using the formula for Boyle's law which is

[tex]P_1V_1 = P_2V_2[/tex]

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume.

Since we're finding the initial volume

[tex]V_1 = \frac{P_2V_2}{P_1} \\[/tex]

We have

[tex]V_1 = \frac{7.98 \times 14.2}{3.14} = \frac{113.316}{3.14} \\ = 36.0878...[/tex]

We have the final answer as

36.09 L

Hope this helps you

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