Answer:
[tex]a'=1.285\ m/s^2[/tex]
Explanation:
Let m be the mass of a little car and m' be the mass of another car.
We know that,
Force = mass × acceleration
ATQ,
m × a = 2m × a'
a = 2 × a'
[tex]a'=\dfrac{a}{2}\\\\a'=\dfrac{2.57}{2}\\\\a'=1.285\ m/s^2[/tex]
So, the acceleration of another little car is equal to [tex]1.285\ m/s^2[/tex].