Answer:
(1) 0.50M in NaCl
(2) 0.25M in H₂SO₄
Explanation:
Problem 1
Molarity = moles of solute / volume of solution expressed in liters
moles of NaCl (solute) = mass(g)/formula wt.(g/mole
= 116 grams/58g/mole = 2 moles
Volume of solution (given) = 4 Liters
Molarity = 2 moles NaCl / 4 Liters Sol'n = 0.50M in NaCl
Problem 2
again, Molarity = moles of solute / volume of solution expressed in liters
Molarity = 3 moles H₂SO₄ / 12 Liters sol'n = 0.25M in H₂SO₄
