A person invested $3,500 in an account growing at a rate allowing the money to double every 15 years. How long, to the nearest tenth of a year would it take for the value of the account to reach$7,700?

Respuesta :

Answer:

30 years and a half

Step-by-step explanation:

well let's just say 3.5k x hmm 2? at an estimate and that will get us to 7000.. so in order to get to 7000 we have to wait 15 years which is 30 years and a half. From Xthermyx. A brainly user.

Answer:

[tex]t = 17.1[/tex]

Step-by-step explanation:

[tex]y = a(2) ^{ \frac{t}{d} } [/tex]

[tex]y = 7700 \: \: a = 3500 \: \: d = 15[/tex]

[tex] \frac{7700}{3500} = \frac{3500(2) ^{ \frac{t}{15} } }{3500} [/tex]

[tex]2.2 = { 2}^{ \frac{t}{15} } [/tex]

[tex] \frac{ log(2.2) }{ log(2) } = \frac{t}{15} [/tex]

[tex]1.1375352 = \frac{t}{15} [/tex]

[tex]15(1.13750352) = t[/tex]

[tex]17.062552856 = t[/tex]

[tex]t = 17.1[/tex]