Given:
The stem-and-leaf table of a data set.
To find:
The median of the given data set.
Solution:
In the stem-and-leaf table 1|2 can be written as 12. So, the data values from the given stem-and-leaf table are:
05, 05, 07, 08, 09, 10, 12, 14, 14, 14, 15, 15, 16, 19, 19, 21, 22, 24, 25, 28
Here, the number of observations = 20, which is an even number. So,
[tex]Median=\dfrac{\dfrac{n}{2}\text{th term}+(\dfrac{n}{2}+1)\text{th term}}{2}[/tex]
[tex]Median=\dfrac{\dfrac{20}{2}\text{th term}+(\dfrac{20}{2}+1)\text{th term}}{2}[/tex]
[tex]Median=\dfrac{10\text{th term}+11\text{th term}}{2}[/tex]
From the given data set, it is clear that the 10th term is 14 and the 11th term is 15.
[tex]Median=\dfrac{14+15}{2}[/tex]
[tex]Median=\dfrac{29}{2}[/tex]
[tex]Median=14.5[/tex]
Therefore, the median number of hits is 14.5.
