Step-by-step explanation:
I will skip question c as there is no subject to solve.
d)
[tex] - 4 + 3(2 - x) = - 8 \\ - 4 + 6 - 3x = - 8 \\ 2 - 3x = - 8 \\ - 3x = - 8 - 2 \\ - 3x = - 10 \\ x = 10 \div 3 \\ = \frac{10}{3} \: or3 \frac{1}{3} [/tex]
e)
[tex]8 - (5 - 9x) = 7(1 - x) \\ 8 - 5 + 9x = 7 - 7x \\ 3 + 9x = 7 - 7x \\ 3 + 9x + 7x = 7 \\ 16x = 7 - 3 \\ 16x = 4 \\ x = 4 \div 16 \\ = \frac{1}{4} [/tex]
[tex] - 5 - 3(x + 1) = - ( - 4x + 1) \\ - 5 - 3x - 3 = 4x - 1 \\ - 8 - 3x = 4x - 1 \\ - 8 - 3x - 4x = - 1 \\ - 7x = - 1 + 8 \\ - 7x = 7 \\ x = 7 \div - 7 \\ = - 1[/tex]
g)
[tex]4 - \frac{6}{9} = \frac{1}{3} + x \\ 4 - \frac{2}{3} = \frac{1}{3} + x \\ x + \frac{1}{3} = 4 - \frac{2}{3} \\ x = 4 - \frac{2}{3} - \frac{1}{3} \\ = 4 - 1 \\ = 3[/tex]
