Write the standard form of the equation of the circle with center (7,1) that also contains the point (−1,−5).

Enter the equation in simplest terms.
pls no links. my computer can't open

Respuesta :

Answer:

[tex](x-7)^2+(y-1)^2=100[/tex]

Step-by-step explanation:

1) Find the radius

We can do this by using the distance equation with the centre (7,1) and the given point (-1,-5):

[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex] where the two points are [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]

Plug in the points (7,1) and (-1,-5)

[tex]d=\sqrt{(-1-7)^2+(-5-1)^2}\\d=\sqrt{(-8)^2+(-6)^2}\\d=\sqrt{64+36}\\d=\sqrt{100}\\d=10[/tex]

Therefore, the radius of the circle is 10 units.

2) Plug the data into the equation of a circle

Equation of a circle (when not centred at the origin):

[tex](x-h)^2+(y-k)^2=r^2[/tex] where the centre is [tex](h,k)[/tex] and r is the radius

Plug in the centre (7,1) as (h,k)

[tex](x-7)^2+(y-1)^2=r^2[/tex]

Plug in the radius 10

[tex](x-7)^2+(y-1)^2=10^2\\(x-7)^2+(y-1)^2=100[/tex]

I hope this helps!