#2: A gas at unknown pressure and a volume of 66 cm has its pressure changed to 150 kPa. The new volume
is 166 cm'. If temperature was kept constant, what was the original pressure of the gas?

Respuesta :

Answer:

377 kPa

Explanation:

The original pressure can be found by using the formula for Boyle's law which is

[tex]P_1V_1 = P_2V_2[/tex]

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we're finding the original pressure

[tex]P_1 = \frac{P_2V_2}{V_1} \\[/tex]

150 kPa = 150,000 Pa

We have

[tex]P_1 = \frac{150000 \times 166}{66} = \frac{24900000}{66} \\ = 377272.72...[/tex]

We have the final answer as

377 kPa

Hope this helps you