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The force between two charges is 2.2 x 10-4 N. One of the charges is changed
and the force becomes 4.4 X 104 N. What change was made to the charge?



Please help me

Respuesta :

Explanation:

Given that,

The force between two charges, [tex]F=2.2\times 10^{-4}\ N[/tex]

New force becomes, [tex]F'=4.4\times 10^{4} N[/tex]

We see that, the new force is 2 times more than the initial force.

The force is directly proportional to the product of forces and inversely to the square of the distance between charges.

It means, one of the charges gets doubled and it results in the doubling of force.

The new charge is 2 ×10⁸ times the old charge.The force is directly proportional to the product of charge;

What is electric force?

The electric force between the two charges is directly propotional to the product of the charge and inversly propotional to the square of the distance between them.

The given data in the problem is;

q₁ is the megnitude of charge 1

q₂ is the megnitude of charge 2

k is the proportionality constant = 9 x 10⁹ Nm² / C²

r is the separated distance

F is the electric force=2.2  x 10-4 N

F' is the new electric force= 4.4 X 104 N.

The force is directly proportional to the product of charge;

[tex]\frac{F'}{F} =2 \times 10^8 \\\\ \frac{q_1 q_2}{q_1'q_2'} = 2 \times 10^8\\\\ \frac{q_1}{q_1'}= 2 \times 10^8 \\\\ q_1=2 \times 10^8 q_1'[/tex]

Hence the new charge is 2 ×10⁸ times the old charge.

To learn more about the electric force refer to the link;

https://brainly.com/question/1076352