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A 52 foot ladder is set against the side of a house so that it reaches up 48 feet. If Jace
grabs the ladder at its base and pulls it 7 feet farther from the house, how far up the
side of the house will the ladder reach now? (The answer is not 41 ft.) Round to the
nearest tenth of a foot.

Respuesta :

okpalawalter8

We have that the  side of the house will the ladder reach given as

x'=45ft

From the question we are told that

52 foot ladder

it reaches up 48 feet

7 feet farther from the house,

Generally the Pythagoras equation for the length is mathematically given as

[tex]x^2+48^2=52^2\\\\x=20[/tex]

Now with the new position the distance of ladder top from ground is

[tex]x'^2+(20+7)^2=52^2\\\\x'=44.4\\\\x'=45ft[/tex]

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