Answer: a=-1
Step-by-step explanation:
Given
[tex]\log_2 (-a+4)=\log _2(3-2a)[/tex]
As the base of both the logarithm is the same. Therefore, the value inside the logarithm is also the same
[tex]\Rightarrow -a+4=3-2a\\\Rightarrow 2a-a=3-4\\\Rightarrow a=-1[/tex]
Thus, the value of a is -1
