Answer:
Triangle BDE and triangle BAC are similar triangles
Hence, two lines DE and AC are parallel to each other
Step-by-step explanation:
For proving that DE is parallel to AC, we are required to prove that triangle BDE and triangle BAC are similar triangles
The ratio of sides of both the triangle must be equal to each other
Hence
[tex]\frac{BE}{DB} = \frac{BC}{BA} \\\frac{16.1}{28} = \frac{20.7+16.1}{64}\\0.575 = 0.575[/tex]
and angle B is common.
Hence the two triangles are similar.
Therefore angle BDE and angle BAC are equal like wise angle BED and angle BCA are equal.
Thus, the two lines DE and AC are parallel to each other
